Well, maybe it’s a really basic question but I cant find how to solve this equation: $ $ \frac{a}{\ln (1+a)}=b$ $ I have tried using the relation of logarithm, making everything to the power of e, but if I do that I just end up with: $ $ \frac{e^{a}}{1+a}=b$ $ So it just becomes into an endless loop where I can’t get the value of a. So if someone has any suggestion, I would highly appreciated. Thank you!